Exercises

  1. Given $ f(x) = x^3 - 10x^2 + 31x - 30$; show that

    $\displaystyle f(0) = -30,\ \ \ \ f(y) = y^3 - 10y^2 + 31y - 30,
$

    $\displaystyle f(2) = 0,\ \ \ \ f(a) = a^3 - 10a^2 + 31a - 30,
$

    $\displaystyle f(3) = f(5),\ \ \ \
f(yz) = y^3z^3 - 10y^2z^2 + 31yz - 30,
$

    $\displaystyle f(1) > f( − 3),\ \ \ \
f(x − 2) = x^3 - 16x^2 + 83x - 140,
$

    $\displaystyle f( - 1) = 6f(6).
$

  2. If $ f(x) = x^3 - 3x + 2$, find $ f(0)$, $ f(1)$, $ f(-1)$, $ f \left ( -\frac{1}{2} \right )$, $ f \left ( \frac{4}{3} \right )$.

  3. If $ f(x) = x^3 - 10x^2 + 31x - 30$, and $ \phi (x) = x^4 − 55x^2 − 210x − 216$, show that

    $ f(2) = \phi ( - 2)$, $ f(3) = \phi( - 3),f(5) = \phi( - 4)$, $ f(0) + \phi (0) + 246 = 0$.

  4. If $ F(x) = 2x$, find $ F(0)$, $ F(-3)$, $ F \left ( \frac{1}{3} \right )$, $ F(-1)$.

  5. Given $ F(x)
= x(x - 1)(x + 6) \left ( x - \frac{1}{2} \right )
\left (x + \frac{5}{4} \right )$, show that $ F(0) = F(1) = F(-6) = F \left (\frac{1}{2} \right )
= F \left ( -\frac{5}{4} \right ) = 0$.

  6. If $ f(m_1) = \frac{m_1 - 1}{m_1 + 1}$, show that $ \frac{f(m_1) - f(m_2)}{1 + f(m_1)f(m_2)} = \frac{m_1 - m_2}{1 + m_1 m_2}$.

  7. If $ \phi (x) = a^x$, show that $ \phi(y) \cdot \phi(z) = \phi(y + z)$.

  8. Given $ \phi(x) = \log \frac{1 - x}{1 + x}$, show that $ \phi(x) + \phi(y) = \phi \left ( \frac{x + y}{1 + xy} \right )$.

  9. If $ f(\phi ) = \cos\phi$, show that $ f(\phi ) = f( - \phi ) = - f(\pi- \phi) = - f(\pi + \phi)$.

  10. If $ F(\theta) = \tan\theta$, show that $ F(2\theta) = \frac{2F(\theta)}{1 - [ F(\theta) ]^2}$.

  11. Given $ \psi(x) = x^{2n} + x^{2m} + 1$, show that $ \psi(1) = 3$, $ \psi(0) = 1$, and $ \psi(a) = \psi(-a)$.

  12. If $ f(x) = \frac{2x - 3}{x + 7}$, find $ f(\sqrt{2})$.

Here's how to verify the double angle identity for $ \tan$ in Exercise 10 above:

[fontsize=\scriptsize,fontfamily=courier,fontshape=tt,frame=single,label=\sage]

sage: theta = var("theta")
sage: tan(2*theta).expand_trig()
2*tan(theta)/(1 - tan(theta)^2)

david joyner 2008-08-11